3.9.24 \(\int \frac {(a+b x^2)^2 \sqrt {c+d x^2}}{\sqrt {e x}} \, dx\) [824]

Optimal. Leaf size=244 \[ \frac {2 \left (5 b^2 c^2-22 a b c d+77 a^2 d^2\right ) \sqrt {e x} \sqrt {c+d x^2}}{231 d^2 e}-\frac {2 b (5 b c-22 a d) \sqrt {e x} \left (c+d x^2\right )^{3/2}}{77 d^2 e}+\frac {2 b^2 (e x)^{5/2} \left (c+d x^2\right )^{3/2}}{11 d e^3}+\frac {2 c^{3/4} \left (5 b^2 c^2-22 a b c d+77 a^2 d^2\right ) \left (\sqrt {c}+\sqrt {d} x\right ) \sqrt {\frac {c+d x^2}{\left (\sqrt {c}+\sqrt {d} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{d} \sqrt {e x}}{\sqrt [4]{c} \sqrt {e}}\right )|\frac {1}{2}\right )}{231 d^{9/4} \sqrt {e} \sqrt {c+d x^2}} \]

[Out]

2/11*b^2*(e*x)^(5/2)*(d*x^2+c)^(3/2)/d/e^3-2/77*b*(-22*a*d+5*b*c)*(d*x^2+c)^(3/2)*(e*x)^(1/2)/d^2/e+2/231*(77*
a^2*d^2-22*a*b*c*d+5*b^2*c^2)*(e*x)^(1/2)*(d*x^2+c)^(1/2)/d^2/e+2/231*c^(3/4)*(77*a^2*d^2-22*a*b*c*d+5*b^2*c^2
)*(cos(2*arctan(d^(1/4)*(e*x)^(1/2)/c^(1/4)/e^(1/2)))^2)^(1/2)/cos(2*arctan(d^(1/4)*(e*x)^(1/2)/c^(1/4)/e^(1/2
)))*EllipticF(sin(2*arctan(d^(1/4)*(e*x)^(1/2)/c^(1/4)/e^(1/2))),1/2*2^(1/2))*(c^(1/2)+x*d^(1/2))*((d*x^2+c)/(
c^(1/2)+x*d^(1/2))^2)^(1/2)/d^(9/4)/e^(1/2)/(d*x^2+c)^(1/2)

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Rubi [A]
time = 0.14, antiderivative size = 244, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 28, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.179, Rules used = {475, 470, 285, 335, 226} \begin {gather*} \frac {2 c^{3/4} \left (\sqrt {c}+\sqrt {d} x\right ) \sqrt {\frac {c+d x^2}{\left (\sqrt {c}+\sqrt {d} x\right )^2}} \left (77 a^2 d^2-22 a b c d+5 b^2 c^2\right ) F\left (2 \text {ArcTan}\left (\frac {\sqrt [4]{d} \sqrt {e x}}{\sqrt [4]{c} \sqrt {e}}\right )|\frac {1}{2}\right )}{231 d^{9/4} \sqrt {e} \sqrt {c+d x^2}}+\frac {2 \sqrt {e x} \sqrt {c+d x^2} \left (77 a^2 d^2-22 a b c d+5 b^2 c^2\right )}{231 d^2 e}-\frac {2 b \sqrt {e x} \left (c+d x^2\right )^{3/2} (5 b c-22 a d)}{77 d^2 e}+\frac {2 b^2 (e x)^{5/2} \left (c+d x^2\right )^{3/2}}{11 d e^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((a + b*x^2)^2*Sqrt[c + d*x^2])/Sqrt[e*x],x]

[Out]

(2*(5*b^2*c^2 - 22*a*b*c*d + 77*a^2*d^2)*Sqrt[e*x]*Sqrt[c + d*x^2])/(231*d^2*e) - (2*b*(5*b*c - 22*a*d)*Sqrt[e
*x]*(c + d*x^2)^(3/2))/(77*d^2*e) + (2*b^2*(e*x)^(5/2)*(c + d*x^2)^(3/2))/(11*d*e^3) + (2*c^(3/4)*(5*b^2*c^2 -
22*a*b*c*d + 77*a^2*d^2)*(Sqrt[c] + Sqrt[d]*x)*Sqrt[(c + d*x^2)/(Sqrt[c] + Sqrt[d]*x)^2]*EllipticF[2*ArcTan[(
d^(1/4)*Sqrt[e*x])/(c^(1/4)*Sqrt[e])], 1/2])/(231*d^(9/4)*Sqrt[e]*Sqrt[c + d*x^2])

Rule 226

Int[1/Sqrt[(a_) + (b_.)*(x_)^4], x_Symbol] :> With[{q = Rt[b/a, 4]}, Simp[(1 + q^2*x^2)*(Sqrt[(a + b*x^4)/(a*(
1 + q^2*x^2)^2)]/(2*q*Sqrt[a + b*x^4]))*EllipticF[2*ArcTan[q*x], 1/2], x]] /; FreeQ[{a, b}, x] && PosQ[b/a]

Rule 285

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c*x)^(m + 1)*((a + b*x^n)^p/(c*(m + n
*p + 1))), x] + Dist[a*n*(p/(m + n*p + 1)), Int[(c*x)^m*(a + b*x^n)^(p - 1), x], x] /; FreeQ[{a, b, c, m}, x]
&& IGtQ[n, 0] && GtQ[p, 0] && NeQ[m + n*p + 1, 0] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 335

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = Denominator[m]}, Dist[k/c, Subst[I
nt[x^(k*(m + 1) - 1)*(a + b*(x^(k*n)/c^n))^p, x], x, (c*x)^(1/k)], x]] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0]
&& FractionQ[m] && IntBinomialQ[a, b, c, n, m, p, x]

Rule 470

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_)), x_Symbol] :> Simp[d*(e*x)^(m +
1)*((a + b*x^n)^(p + 1)/(b*e*(m + n*(p + 1) + 1))), x] - Dist[(a*d*(m + 1) - b*c*(m + n*(p + 1) + 1))/(b*(m +
n*(p + 1) + 1)), Int[(e*x)^m*(a + b*x^n)^p, x], x] /; FreeQ[{a, b, c, d, e, m, n, p}, x] && NeQ[b*c - a*d, 0]
&& NeQ[m + n*(p + 1) + 1, 0]

Rule 475

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^2, x_Symbol] :> Simp[d^2*(e*x)^(
m + n + 1)*((a + b*x^n)^(p + 1)/(b*e^(n + 1)*(m + n*(p + 2) + 1))), x] + Dist[1/(b*(m + n*(p + 2) + 1)), Int[(
e*x)^m*(a + b*x^n)^p*Simp[b*c^2*(m + n*(p + 2) + 1) + d*((2*b*c - a*d)*(m + n + 1) + 2*b*c*n*(p + 1))*x^n, x],
x], x] /; FreeQ[{a, b, c, d, e, m, n, p}, x] && NeQ[b*c - a*d, 0] && IGtQ[n, 0] && NeQ[m + n*(p + 2) + 1, 0]

Rubi steps

\begin {align*} \int \frac {\left (a+b x^2\right )^2 \sqrt {c+d x^2}}{\sqrt {e x}} \, dx &=\frac {2 b^2 (e x)^{5/2} \left (c+d x^2\right )^{3/2}}{11 d e^3}+\frac {2 \int \frac {\sqrt {c+d x^2} \left (\frac {11 a^2 d}{2}-\frac {1}{2} b (5 b c-22 a d) x^2\right )}{\sqrt {e x}} \, dx}{11 d}\\ &=-\frac {2 b (5 b c-22 a d) \sqrt {e x} \left (c+d x^2\right )^{3/2}}{77 d^2 e}+\frac {2 b^2 (e x)^{5/2} \left (c+d x^2\right )^{3/2}}{11 d e^3}-\frac {1}{77} \left (-77 a^2-\frac {b c (5 b c-22 a d)}{d^2}\right ) \int \frac {\sqrt {c+d x^2}}{\sqrt {e x}} \, dx\\ &=\frac {2 \left (77 a^2+\frac {b c (5 b c-22 a d)}{d^2}\right ) \sqrt {e x} \sqrt {c+d x^2}}{231 e}-\frac {2 b (5 b c-22 a d) \sqrt {e x} \left (c+d x^2\right )^{3/2}}{77 d^2 e}+\frac {2 b^2 (e x)^{5/2} \left (c+d x^2\right )^{3/2}}{11 d e^3}+\frac {1}{231} \left (2 c \left (77 a^2+\frac {b c (5 b c-22 a d)}{d^2}\right )\right ) \int \frac {1}{\sqrt {e x} \sqrt {c+d x^2}} \, dx\\ &=\frac {2 \left (77 a^2+\frac {b c (5 b c-22 a d)}{d^2}\right ) \sqrt {e x} \sqrt {c+d x^2}}{231 e}-\frac {2 b (5 b c-22 a d) \sqrt {e x} \left (c+d x^2\right )^{3/2}}{77 d^2 e}+\frac {2 b^2 (e x)^{5/2} \left (c+d x^2\right )^{3/2}}{11 d e^3}+\frac {\left (4 c \left (77 a^2+\frac {b c (5 b c-22 a d)}{d^2}\right )\right ) \text {Subst}\left (\int \frac {1}{\sqrt {c+\frac {d x^4}{e^2}}} \, dx,x,\sqrt {e x}\right )}{231 e}\\ &=\frac {2 \left (77 a^2+\frac {b c (5 b c-22 a d)}{d^2}\right ) \sqrt {e x} \sqrt {c+d x^2}}{231 e}-\frac {2 b (5 b c-22 a d) \sqrt {e x} \left (c+d x^2\right )^{3/2}}{77 d^2 e}+\frac {2 b^2 (e x)^{5/2} \left (c+d x^2\right )^{3/2}}{11 d e^3}+\frac {2 c^{3/4} \left (77 a^2+\frac {b c (5 b c-22 a d)}{d^2}\right ) \left (\sqrt {c}+\sqrt {d} x\right ) \sqrt {\frac {c+d x^2}{\left (\sqrt {c}+\sqrt {d} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac {\sqrt [4]{d} \sqrt {e x}}{\sqrt [4]{c} \sqrt {e}}\right )|\frac {1}{2}\right )}{231 \sqrt [4]{d} \sqrt {e} \sqrt {c+d x^2}}\\ \end {align*}

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Mathematica [C] Result contains complex when optimal does not.
time = 10.16, size = 189, normalized size = 0.77 \begin {gather*} \frac {\sqrt {x} \left (\frac {2 \sqrt {x} \left (c+d x^2\right ) \left (77 a^2 d^2+22 a b d \left (2 c+3 d x^2\right )+b^2 \left (-10 c^2+6 c d x^2+21 d^2 x^4\right )\right )}{d^2}+\frac {4 i c \left (5 b^2 c^2-22 a b c d+77 a^2 d^2\right ) \sqrt {1+\frac {c}{d x^2}} x F\left (\left .i \sinh ^{-1}\left (\frac {\sqrt {\frac {i \sqrt {c}}{\sqrt {d}}}}{\sqrt {x}}\right )\right |-1\right )}{\sqrt {\frac {i \sqrt {c}}{\sqrt {d}}} d^2}\right )}{231 \sqrt {e x} \sqrt {c+d x^2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((a + b*x^2)^2*Sqrt[c + d*x^2])/Sqrt[e*x],x]

[Out]

(Sqrt[x]*((2*Sqrt[x]*(c + d*x^2)*(77*a^2*d^2 + 22*a*b*d*(2*c + 3*d*x^2) + b^2*(-10*c^2 + 6*c*d*x^2 + 21*d^2*x^
4)))/d^2 + ((4*I)*c*(5*b^2*c^2 - 22*a*b*c*d + 77*a^2*d^2)*Sqrt[1 + c/(d*x^2)]*x*EllipticF[I*ArcSinh[Sqrt[(I*Sq
rt[c])/Sqrt[d]]/Sqrt[x]], -1])/(Sqrt[(I*Sqrt[c])/Sqrt[d]]*d^2)))/(231*Sqrt[e*x]*Sqrt[c + d*x^2])

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Maple [A]
time = 0.11, size = 401, normalized size = 1.64

method	result	size
risch	\(\frac {2 \left (21 b^{2} x^{4} d^{2}+66 a b \,d^{2} x^{2}+6 b^{2} c d \,x^{2}+77 a^{2} d^{2}+44 a b c d -10 b^{2} c^{2}\right ) x \sqrt {d \,x^{2}+c}}{231 d^{2} \sqrt {e x}}+\frac {2 c \left (77 a^{2} d^{2}-22 a b c d +5 b^{2} c^{2}\right ) \sqrt {-c d}\, \sqrt {\frac {\left (x +\frac {\sqrt {-c d}}{d}\right ) d}{\sqrt {-c d}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-c d}}{d}\right ) d}{\sqrt {-c d}}}\, \sqrt {-\frac {x d}{\sqrt {-c d}}}\, \EllipticF \left (\sqrt {\frac {\left (x +\frac {\sqrt {-c d}}{d}\right ) d}{\sqrt {-c d}}}, \frac {\sqrt {2}}{2}\right ) \sqrt {e x \left (d \,x^{2}+c \right )}}{231 d^{3} \sqrt {d e \,x^{3}+c e x}\, \sqrt {e x}\, \sqrt {d \,x^{2}+c}}\)	\(236\)
elliptic	\(\frac {\sqrt {e x \left (d \,x^{2}+c \right )}\, \left (\frac {2 b^{2} x^{4} \sqrt {d e \,x^{3}+c e x}}{11 e}+\frac {2 \left (2 a b d +\frac {2}{11} b^{2} c \right ) x^{2} \sqrt {d e \,x^{3}+c e x}}{7 d e}+\frac {2 \left (a^{2} d +2 a b c -\frac {5 c \left (2 a b d +\frac {2}{11} b^{2} c \right )}{7 d}\right ) \sqrt {d e \,x^{3}+c e x}}{3 d e}+\frac {\left (a^{2} c -\frac {c \left (a^{2} d +2 a b c -\frac {5 c \left (2 a b d +\frac {2}{11} b^{2} c \right )}{7 d}\right )}{3 d}\right ) \sqrt {-c d}\, \sqrt {\frac {\left (x +\frac {\sqrt {-c d}}{d}\right ) d}{\sqrt {-c d}}}\, \sqrt {-\frac {2 \left (x -\frac {\sqrt {-c d}}{d}\right ) d}{\sqrt {-c d}}}\, \sqrt {-\frac {x d}{\sqrt {-c d}}}\, \EllipticF \left (\sqrt {\frac {\left (x +\frac {\sqrt {-c d}}{d}\right ) d}{\sqrt {-c d}}}, \frac {\sqrt {2}}{2}\right )}{d \sqrt {d e \,x^{3}+c e x}}\right )}{\sqrt {e x}\, \sqrt {d \,x^{2}+c}}\)	\(289\)
default	\(\frac {\frac {2 b^{2} d^{4} x^{7}}{11}+\frac {2 \sqrt {\frac {d x +\sqrt {-c d}}{\sqrt {-c d}}}\, \sqrt {2}\, \sqrt {\frac {-d x +\sqrt {-c d}}{\sqrt {-c d}}}\, \sqrt {-\frac {x d}{\sqrt {-c d}}}\, \EllipticF \left (\sqrt {\frac {d x +\sqrt {-c d}}{\sqrt {-c d}}}, \frac {\sqrt {2}}{2}\right ) \sqrt {-c d}\, a^{2} c \,d^{2}}{3}-\frac {4 \sqrt {\frac {d x +\sqrt {-c d}}{\sqrt {-c d}}}\, \sqrt {2}\, \sqrt {\frac {-d x +\sqrt {-c d}}{\sqrt {-c d}}}\, \sqrt {-\frac {x d}{\sqrt {-c d}}}\, \EllipticF \left (\sqrt {\frac {d x +\sqrt {-c d}}{\sqrt {-c d}}}, \frac {\sqrt {2}}{2}\right ) \sqrt {-c d}\, a b \,c^{2} d}{21}+\frac {10 \sqrt {\frac {d x +\sqrt {-c d}}{\sqrt {-c d}}}\, \sqrt {2}\, \sqrt {\frac {-d x +\sqrt {-c d}}{\sqrt {-c d}}}\, \sqrt {-\frac {x d}{\sqrt {-c d}}}\, \EllipticF \left (\sqrt {\frac {d x +\sqrt {-c d}}{\sqrt {-c d}}}, \frac {\sqrt {2}}{2}\right ) \sqrt {-c d}\, b^{2} c^{3}}{231}+\frac {4 a b \,d^{4} x^{5}}{7}+\frac {18 b^{2} c \,d^{3} x^{5}}{77}+\frac {2 a^{2} d^{4} x^{3}}{3}+\frac {20 a b c \,d^{3} x^{3}}{21}-\frac {8 b^{2} c^{2} d^{2} x^{3}}{231}+\frac {2 a^{2} c \,d^{3} x}{3}+\frac {8 a b \,c^{2} d^{2} x}{21}-\frac {20 b^{2} c^{3} d x}{231}}{\sqrt {d \,x^{2}+c}\, \sqrt {e x}\, d^{3}}\)	\(401\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^2+a)^2*(d*x^2+c)^(1/2)/(e*x)^(1/2),x,method=_RETURNVERBOSE)

[Out]

2/231/(d*x^2+c)^(1/2)*(21*b^2*d^4*x^7+77*((d*x+(-c*d)^(1/2))/(-c*d)^(1/2))^(1/2)*2^(1/2)*((-d*x+(-c*d)^(1/2))/
(-c*d)^(1/2))^(1/2)*(-x/(-c*d)^(1/2)*d)^(1/2)*EllipticF(((d*x+(-c*d)^(1/2))/(-c*d)^(1/2))^(1/2),1/2*2^(1/2))*(
-c*d)^(1/2)*a^2*c*d^2-22*((d*x+(-c*d)^(1/2))/(-c*d)^(1/2))^(1/2)*2^(1/2)*((-d*x+(-c*d)^(1/2))/(-c*d)^(1/2))^(1
/2)*(-x/(-c*d)^(1/2)*d)^(1/2)*EllipticF(((d*x+(-c*d)^(1/2))/(-c*d)^(1/2))^(1/2),1/2*2^(1/2))*(-c*d)^(1/2)*a*b*
c^2*d+5*((d*x+(-c*d)^(1/2))/(-c*d)^(1/2))^(1/2)*2^(1/2)*((-d*x+(-c*d)^(1/2))/(-c*d)^(1/2))^(1/2)*(-x/(-c*d)^(1
/2)*d)^(1/2)*EllipticF(((d*x+(-c*d)^(1/2))/(-c*d)^(1/2))^(1/2),1/2*2^(1/2))*(-c*d)^(1/2)*b^2*c^3+66*a*b*d^4*x^
5+27*b^2*c*d^3*x^5+77*a^2*d^4*x^3+110*a*b*c*d^3*x^3-4*b^2*c^2*d^2*x^3+77*a^2*c*d^3*x+44*a*b*c^2*d^2*x-10*b^2*c
^3*d*x)/(e*x)^(1/2)/d^3

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^2+a)^2*(d*x^2+c)^(1/2)/(e*x)^(1/2),x, algorithm="maxima")

[Out]

e^(-1/2)*integrate((b*x^2 + a)^2*sqrt(d*x^2 + c)/sqrt(x), x)

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Fricas [C] Result contains higher order function than in optimal. Order 9 vs. order 4.
time = 0.27, size = 119, normalized size = 0.49 \begin {gather*} \frac {2 \, {\left (2 \, {\left (5 \, b^{2} c^{3} - 22 \, a b c^{2} d + 77 \, a^{2} c d^{2}\right )} \sqrt {d} {\rm weierstrassPInverse}\left (-\frac {4 \, c}{d}, 0, x\right ) + {\left (21 \, b^{2} d^{3} x^{4} - 10 \, b^{2} c^{2} d + 44 \, a b c d^{2} + 77 \, a^{2} d^{3} + 6 \, {\left (b^{2} c d^{2} + 11 \, a b d^{3}\right )} x^{2}\right )} \sqrt {d x^{2} + c} \sqrt {x}\right )} e^{\left (-\frac {1}{2}\right )}}{231 \, d^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^2+a)^2*(d*x^2+c)^(1/2)/(e*x)^(1/2),x, algorithm="fricas")

[Out]

2/231*(2*(5*b^2*c^3 - 22*a*b*c^2*d + 77*a^2*c*d^2)*sqrt(d)*weierstrassPInverse(-4*c/d, 0, x) + (21*b^2*d^3*x^4
- 10*b^2*c^2*d + 44*a*b*c*d^2 + 77*a^2*d^3 + 6*(b^2*c*d^2 + 11*a*b*d^3)*x^2)*sqrt(d*x^2 + c)*sqrt(x))*e^(-1/2
)/d^3

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Sympy [C] Result contains complex when optimal does not.
time = 3.46, size = 150, normalized size = 0.61 \begin {gather*} \frac {a^{2} \sqrt {c} \sqrt {x} \Gamma \left (\frac {1}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {1}{4} \\ \frac {5}{4} \end {matrix}\middle | {\frac {d x^{2} e^{i \pi }}{c}} \right )}}{2 \sqrt {e} \Gamma \left (\frac {5}{4}\right )} + \frac {a b \sqrt {c} x^{\frac {5}{2}} \Gamma \left (\frac {5}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {5}{4} \\ \frac {9}{4} \end {matrix}\middle | {\frac {d x^{2} e^{i \pi }}{c}} \right )}}{\sqrt {e} \Gamma \left (\frac {9}{4}\right )} + \frac {b^{2} \sqrt {c} x^{\frac {9}{2}} \Gamma \left (\frac {9}{4}\right ) {{}_{2}F_{1}\left (\begin {matrix} - \frac {1}{2}, \frac {9}{4} \\ \frac {13}{4} \end {matrix}\middle | {\frac {d x^{2} e^{i \pi }}{c}} \right )}}{2 \sqrt {e} \Gamma \left (\frac {13}{4}\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x**2+a)**2*(d*x**2+c)**(1/2)/(e*x)**(1/2),x)

[Out]

a**2*sqrt(c)*sqrt(x)*gamma(1/4)*hyper((-1/2, 1/4), (5/4,), d*x**2*exp_polar(I*pi)/c)/(2*sqrt(e)*gamma(5/4)) +
a*b*sqrt(c)*x**(5/2)*gamma(5/4)*hyper((-1/2, 5/4), (9/4,), d*x**2*exp_polar(I*pi)/c)/(sqrt(e)*gamma(9/4)) + b*
*2*sqrt(c)*x**(9/2)*gamma(9/4)*hyper((-1/2, 9/4), (13/4,), d*x**2*exp_polar(I*pi)/c)/(2*sqrt(e)*gamma(13/4))

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^2+a)^2*(d*x^2+c)^(1/2)/(e*x)^(1/2),x, algorithm="giac")

[Out]

integrate((b*x^2 + a)^2*sqrt(d*x^2 + c)*e^(-1/2)/sqrt(x), x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {{\left (b\,x^2+a\right )}^2\,\sqrt {d\,x^2+c}}{\sqrt {e\,x}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((a + b*x^2)^2*(c + d*x^2)^(1/2))/(e*x)^(1/2),x)

[Out]

int(((a + b*x^2)^2*(c + d*x^2)^(1/2))/(e*x)^(1/2), x)

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